Discussion

Let image. For what value of x does image for all values of y?

(A)

0

(B)...
(C)...
(D)...
(E)...
(F)...
*This question is included in Nova Math - Problem Set C: Defined Function, question #9

The solution is

Posted: 10/21/2013 17:00
Confused on how A is the answer
Image Not Available
Contributor
Posted: 10/29/2013 17:22
Hi Meru, have you tried to follow the explanation? If you are still confused please post again.
Posted: 10/31/2013 19:13
I didn't get it, it's so confusing...
Image Not Available
Contributor
Posted: 11/01/2013 14:15
Hello Jayden, and also Meru.

Here, x⊝y is defined as x√y - y - 2x. We are asked, what values of x will set x⊝y = -y?

So all we have to do is set x√y - y - 2x = -y, and solve for x.

x√y - y - 2x = -y;
x√y - 2x = 0, then through associative property: x(√y -2) = 0

In order for that last equation to be true regardless of what y is, x has to be 0. So A is the answer.
Posted: 04/17/2014 17:00
What if x=0? It's still equal 0
| Edit
Posted: 04/21/2014 13:45
Yini, exactly the point. If x=0, then regardless of what y is, x (√y - 2) will be = 0. So, if x = 0, x⊝y = -y, regardless of what y is.
| Edit
Posted: 04/13/2014 22:57
I think E is the correct answer.
Posted: 04/17/2014 16:59
what if x equal 0? Then, x(/y-2) still equal 0, so I think the answer is E
Posted: 04/21/2014 13:46
Yini, please see the explanation by Joel Brainer in the discussion thread. We are looking for a value of x that will make the equation x⊝y = -y true regardless of the value of y.

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