Discussion
What is the value of the 201st term of a sequence if the first term of the sequence is 2 and each successive term is 4 more than the term immediately preceding it?
*This question is included in Nova Math - Diagnostic/Review:, question #27
| (A) | 798 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 07/25/2013 16:44
I've read the solution and still don't understand how to figure this out at all. Please advise.
Posted: 07/27/2013 02:53
David, say you start with 2. That's the first term. Then you add 4, 2+4=6, that's the 2nd term, or 4*1 + 2. 3rd term = 6+4 = 10 or 4*2 +2. 4th term = 10 + 4 = 14, or 4*3 +2. That means the 201th term = 4*200 +2 = 802.