Discussion
If x is an integer and y = −3x + 7, what is the least value of x for which y is less than 1?
| (A) | 1 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 05/11/2013 15:11
How do you do this problem?
Posted: 05/14/2013 13:57
Maggie, did you check the Solution yet :) ?
y = -3x + 7; the question is asking about the least value of x for which y < 1.
So -3x + 7 < 1, or -3x < -6. Further simplifying, we can divide both sides by -3, but remember that dividing an inequality by a negative number flips the sign. So we get x > 2. This means, as long as x is larger than 2, y is less than 1. The least x possible is 3.
y = -3x + 7; the question is asking about the least value of x for which y < 1.
So -3x + 7 < 1, or -3x < -6. Further simplifying, we can divide both sides by -3, but remember that dividing an inequality by a negative number flips the sign. So we get x > 2. This means, as long as x is larger than 2, y is less than 1. The least x possible is 3.