Discussion
| Column A x3 + 1 |
x > 0 | Column B x4 + 1 |
| (A) | Column A is larger |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 10/22/2012 23:38
The answer says "if x=0 or 1" however x >0 is defined above.
Posted: 10/23/2012 00:29
Hi Mona, thanks for the input. You can replace "if x=0 or 1" with simply "if x=1 ...".
Posted: 12/17/2013 11:07
It is clearly said that x>0 then how will the argument if x=0 hold good. The answer is B?
Posted: 12/18/2013 16:50
Sheeman, the explanation should read:
"Now, if x = 1, then the expressions are equal. However, for any other positive value of x, the expressions are unequal."
"Now, if x = 1, then the expressions are equal. However, for any other positive value of x, the expressions are unequal."
Posted: 12/17/2013 11:08
Answer is D, but not with the argument x=0 but x=1/4
Posted: 01/06/2014 21:31
The answer is d but I don't understand why column b would not be correct
Posted: 01/13/2014 17:30
Darrielle, is x=1, for example, the columns would be equal, and B is not larger than A.
Posted: 01/19/2014 08:29
Where do you get x=1? I don't see that in the answer key. All I see is x=0 but the question is not saying x=0 it's saying X>0. Also when facing questions like x>0 or x
Posted: 01/19/2014 20:46
The solution should have said "Now, if x = 1, then the expressions are equal. However, for any other positive value of x, the expressions are unequal."
Posted: 07/19/2015 13:30
Is it x^(3+1) and 4^(4+1) OR x^(3)+1 and x^(4)+1?
Posted: 07/19/2015 14:14
Hi Arseniy,
It is x^(3)+1 and x^(4)+1. That is, the 1s are not exponents. To make it clearer, we can write the 1s first:
1 + x^3
[read, 1 plus x cubed]
and
1 + x^4
[read, 1 plus x to the fourth power]
Nova Press
It is x^(3)+1 and x^(4)+1. That is, the 1s are not exponents. To make it clearer, we can write the 1s first:
1 + x^3
[read, 1 plus x cubed]
and
1 + x^4
[read, 1 plus x to the fourth power]
Nova Press