Discussion
The buyer of a particular car must choose 2 of 3 optional colors and 3 of 4 optional luxury features. In how many different ways can the buyer select the colors and luxury features?
*This question is included in Nova Math - Problem Set Z: Miscellaneous Problems, question #4
| (A) | 3 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 09/30/2012 16:26
Ok but your only suppose to choose 2 cars?
Posted: 10/01/2012 13:14
Chima, no, you are not supposed to choose 2 cars. It is 1 car, with color options (e.g., red, white, and blue) and luxury feature options (e.g., A, B, C, D, for simplicity's sake).
The question is asking the number of different ways in which a buyer can combine the color options, and the luxury options. Start with the color: you can do [red, white], [red,blue], [blue,white], so 3 ways. Luxury options: [A,B,C], [A,B,D], [A,C,D], [B,C,D], so 4 ways.
When you combine the color options and the luxury options, it's 3 x 4 = 12.
The question is asking the number of different ways in which a buyer can combine the color options, and the luxury options. Start with the color: you can do [red, white], [red,blue], [blue,white], so 3 ways. Luxury options: [A,B,C], [A,B,D], [A,C,D], [B,C,D], so 4 ways.
When you combine the color options and the luxury options, it's 3 x 4 = 12.