Discussion
If a, b, and c are consecutive integers and a < b < c, which of the following must be true?
*This question is included in Nova Math - Diagnostic/Review:, question #8
| (A) | b2 is a prime number |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 09/16/2012 14:03
I don't see the (a+1) + 1 = a+2.?
I got the answer, but by using 2 sets of numbers and calculating...
I got the answer, but by using 2 sets of numbers and calculating...
Posted: 09/19/2012 17:56
Dusty, not quite sure what your question was.
a, b, c are consecutive integers, therefore b = a+1; and c=b+1 = (a+1)+1 = a + 2.
If you used 2 sets of numbers and used substitution, that was a good way to solve this problem too.
a, b, c are consecutive integers, therefore b = a+1; and c=b+1 = (a+1)+1 = a + 2.
If you used 2 sets of numbers and used substitution, that was a good way to solve this problem too.
Posted: 09/18/2015 15:42
If you let a= -1 and b= -2 and c= 3, then doesn't a+b/2 = -1 and not b?