Discussion
The sum of the digits of a two-digit number is 12, and the ten’s digit is one-third the unit’s digit. What is the number?
*This question is included in Nova Math - Problem Set B: Substitution (Plugging in), question #4
| (A) | 93 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 09/05/2012 23:53
I do t get how it says
one third of the digit ....
one third of the digit ....
Posted: 09/07/2012 20:06
Aidet, here is how you set it up:
There are 2 digits in a number: x and y. x is the ten's part, and y is the unit part.
According to the information given:
x + y = 12
x = 1/3 * y
You have 2 equations with 2 unknowns, which should be easy to solve ...
There are 2 digits in a number: x and y. x is the ten's part, and y is the unit part.
According to the information given:
x + y = 12
x = 1/3 * y
You have 2 equations with 2 unknowns, which should be easy to solve ...
Posted: 11/21/2012 10:49
Yes, in this case you get 4/3 y = 12, which yields y=9.
Posted: 03/15/2015 11:37
Thx