Discussion
After being marked down 20 percent, a calculator sells for $10. The original selling price was
*This question is included in Nova Math - Problem Set K: Elimination Strategies, question #3
| (A) | $20 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 07/20/2012 10:47
without doing the elimination process, what is other way to do it because I am confused to this elimination process
Posted: 07/20/2012 13:40
The formal way to do it is this way.
We are supposed to find the original selling price x.
x - (20% ⋅ x) = 10
80%⋅x = 10
Think about it: after being marked down by 20%, we are left with 80% of x, which is equal to 10. Now we can solve for x, the original price. Multiply both sides by 100/80.
x = 10 ⋅ 100/80
x = 12.5
We are supposed to find the original selling price x.
x - (20% ⋅ x) = 10
80%⋅x = 10
Think about it: after being marked down by 20%, we are left with 80% of x, which is equal to 10. Now we can solve for x, the original price. Multiply both sides by 100/80.
x = 10 ⋅ 100/80
x = 12.5