Discussion
Column A | Column B | |
1 | ⎮x⎮ |
(A) | Column A is larger |
(B) | ... |
(C) | ... |
(D) | ... |
(E) | ... |
(F) | ... |
The solution is
Posted: 11/11/2012 23:57
Is there a formatting error on this question, because it is not making sense to me?
Posted: 11/13/2012 00:44
Larry Soileau, our apology. Have you updated to the latest version via the app store? Because we fixed this problem. If you still cannot see the picture on the app, here it is:
Column A: 1
Column B: |x|
Conditions: x is not 0; |x| divided by x = 1
Column A: 1
Column B: |x|
Conditions: x is not 0; |x| divided by x = 1
Posted: 11/27/2012 11:38
I have version 1.2 and still cannot read the whole problem.
Posted: 11/27/2012 11:45
Josh, here is the problem in its entirety:
Conditions: x is not 0; |x| divided by x = 1
Column A: 1
Column B: |x|
Conditions: x is not 0; |x| divided by x = 1
Column A: 1
Column B: |x|
Posted: 01/07/2013 20:53
Instead of absolute value sign there are two boxes on either side of x
Posted: 01/08/2013 01:25
Sorry Justin. The errata was posted in the prior thread.
Posted: 11/09/2014 18:35
It still shows up as two boxes in column b...