Discussion
Define a @ b to be a3 – 1.
*This question is included in Nova Math - Diagnostic/Review:, question #29
Column A | Column B | |
x @ 1 | x @ 10 |
(A) | Column A is larger |
(B) | ... |
(C) | ... |
(D) | ... |
(E) | ... |
(F) | ... |
The solution is
Posted: 04/14/2012 15:29
How they come to this conclusion? Why x^3-1 is equal at x@10?
Posted: 04/15/2012 07:44
have no idea why come to this conclusion
Posted: 04/16/2012 00:16
Hi Tanya and Vicki. This is a defined function question. It is always useful to think of, or restate the defined function formally as ƒ(x). In this case, a@b can be written as ƒ(a,b) = a^3-1, hence b doesn't play a part at all. Hence in x@1, you can ignore 1. It is ƒ(x) = x^3 - 1. The same goes for x@10, you can ignore 10 since the b part or 10 does not play a role. So x@10=ƒ(x) = x^3 -1.
Hence they are equal.
Hence they are equal.
Posted: 04/16/2012 02:14
Aaaaah, ok... Now I understand !!!
Thanks a lot)))
Thanks a lot)))
Posted: 04/16/2012 19:10
Done))
Posted: 04/16/2012 02:17
You are welcome Tanya. Please don't forget to rate us in the App Store. Thanks for using our app and good luck in your preparation.
Posted: 04/17/2012 06:52
It's very nice of you to help me to work out problem in such short time. Thank you so much! I won't forget to comment on app store^^
Posted: 08/21/2013 18:29
I need more explanation to this problem... I'm kinda confused
Posted: 08/30/2013 12:43
Paul, Joel Brainer posted a good explanation. Please look up the thread. Thanks.
Posted: 11/06/2013 12:22
Why does column B not = x3-10?
Including the "b" in the initial statement makes it seem that the second number IS relevant.
Including the "b" in the initial statement makes it seem that the second number IS relevant.
Posted: 11/08/2013 15:07
Liam, "b" seems relevant, but it is not. The function's outcome is a^3 -1, not a^3-b.