Discussion
How many different ways can 3 cubes be painted if each cube is painted one color and only the 3 colors red, blue, and green are available? (Order is not considered, for example, green, green, blue is considered the same as green, blue, green.)
*This question is included in Nova Math - Problem Set K: Elimination Strategies, question #7
| (A) | 2 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 03/15/2012 19:20
What an awful explanation, I'm sorry; but the real explanation is this:
since there are 6 sides of a cube and every cube is given one color automatically, the other 5 sides can have any combination of the 3 stated colors. So you'd do:
5![3!•2!] which is 120/(6•2) which is equal to 10.
since there are 6 sides of a cube and every cube is given one color automatically, the other 5 sides can have any combination of the 3 stated colors. So you'd do:
5![3!•2!] which is 120/(6•2) which is equal to 10.