Discussion
If a, b, and c are consecutive integers and a < b < c, which of the following must be true?
| (A) | b2 is a prime number |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 01/07/2012 17:47
What is a consecutive integer?
Posted: 01/08/2012 18:30
2 is consecutive to 1
2 is successive to 1
2 is the next element without interruption from 1
Z is consecutive of Y
In this case it is presumed you will choose number set N by default which consists of all our natural numbers we use to count, thus all positive integers ergo 1, 2, 3, etc.
2 is successive to 1
2 is the next element without interruption from 1
Z is consecutive of Y
In this case it is presumed you will choose number set N by default which consists of all our natural numbers we use to count, thus all positive integers ergo 1, 2, 3, etc.
Posted: 08/13/2012 10:51
Suppose x x+1 and x-1 as a result they are required in the question. Than a=x-1. b=x. c=x+1 a+c=2x is two b as you see.
Posted: 01/11/2012 12:51
Shelby, consecutive integers are integers that are next to each other, like 1,2,3 or 2,3,4, or 3,4,5 or 100, 101, 102, and so on. Then you can quickly plug in the samples of consecutive integers into the choices, and find out the right answer.
Posted: 11/02/2012 10:08
Wow thank you so much!!!
Posted: 05/29/2012 23:06
Can you explain why it couldn't be both B and E? (Aside from the fact that there isn't allowed to be two answers...)
Posted: 05/30/2012 00:17
Kyle, the question states 'must be true'.
While answer B remains true if we take the consecutive integers a=0, b=1 and c=2, it's answer E that ceases being true always.
Answer B:
( 0 + 2 ) / 2 = 1 == TRUE
Answer E:
2 - 0 = 1 == FALSE
Niels
While answer B remains true if we take the consecutive integers a=0, b=1 and c=2, it's answer E that ceases being true always.
Answer B:
( 0 + 2 ) / 2 = 1 == TRUE
Answer E:
2 - 0 = 1 == FALSE
Niels
Posted: 10/26/2012 06:44
What is a 'consecutive integer'??
Posted: 12/04/2012 16:10
It is impossible that b^2 be a prime number (b*b), so (A)'s out. Consecutive integers follow the pattern even, odd, even, odd... So (C)'s out. ab/3 is not always an integer, so (D)'s out. c-a doesn't always equal to b, so there goes (E). Hence, the answer is (B). By the way, if you think of consecutive number, the middle one is always the median.
Posted: 12/05/2012 05:03
Federico,
I get that you're anxious and enthusiastic, but "By the way, if you think of consecutive number, the middle one is always the median."
This insinuates there's a direct relation between a consecutive number and the median while there's not. ;)
Niels
I get that you're anxious and enthusiastic, but "By the way, if you think of consecutive number, the middle one is always the median."
This insinuates there's a direct relation between a consecutive number and the median while there's not. ;)
Niels
Posted: 12/12/2012 12:45
Niels, you gotta be kidding me. No one is perfect at grammar (in fact, i got 590 or something like that on the PSAT.). Plus, I'm ESL, so I may sometimes intrude wrong grammar...
Good thing that you already know that now.
Good thing that you already know that now.
Posted: 12/12/2012 13:57
Federico,
Blaming this on grammar is the wrong choice.
I'm sure I am not the one 'kidding you'.
Niels
Blaming this on grammar is the wrong choice.
I'm sure I am not the one 'kidding you'.
Niels