If digits 1, 2, 0, 3, 4 (a) occur once, (b) the second digit has twice the value as the first, and (c) the third value is less than the fifth, then what is wrong with the order of the sequence of the five digits above?

K Glenn,
I think you read the Question Stem wrong.

You're looking for the answer choice that cannot be an acceptable product code.

A walk-thru of Q 4.

The walkthroughs are better when you draw it out like you did here. Some just have a recording;-(. However, your time and help is appreciated. Thanks

Hey Daniel,

Let us know which ones only have a recording. They should all be drawn out like this one is.

Thanks. We appreciate your feedback.

- Arcadia

How can 4 be the third or fourth number when the second number is exactly twice the first

Maddison,

If "1" is first, and "2" is second, then the condition "the second number is exactly twice the first" is satisfied.

So, for example, you can have 1, 2, 3, 0, 4.

I was not sure why 3/4 was the correct answer for question. Someone please explain?

Sasha, please follow the discussion thread. There was a video walkthrough that explained it and set up the problem step by step.

Sasha, after you follow the explanation and you still have questions, please post and be specific about what you don't understand.

If the third digit for an acceptable product code is not 0, and the sequence 0 2 1 4 3 satisfies an "acceptable" definition, how can option C (The fourth digit of the product code is 0) a correct response?

Chad, 0, 2, 1, 4, 3 is not acceptable code because of the 3rd rule which states that the 2nd digit is twice as much as the 1st digit. All acceptable codes will only start with 1,2 or 2,4.

Thank you for posting, James.