Discussion
If none of the windows contains both rose glass and
orange glass, then the complete color combination of
the glass in one of the windows must be
*This question is included in PT 62 LG, question #13
(A) | green and purple |
(B) | ... |
(C) | ... |
(D) | ... |
(E) | ... |
(F) | ... |
The solution is
Posted: 08/16/2011 10:23
I don't understand this one either
Posted: 08/17/2011 01:58
This game is a pain, so don't sweat it if it leaves you scratching your head a bit.
Here's the setup:
G, O, P, R, Y
Rule 1: (G + P) x1 *exactly*
Rule 2: R x2 *exactly*
Rule 3: Y --> ~G, ~O
Rule 4: ~P --> O
CPos 3: (O or G) --> ~Y
CPos 4: ~O --> P
Rule 3 + CPos 4: Y --> ~O --> P
___ ___ ___ ___
P/O
___ ___ ___ ___
P/O
___ ___ ___ ___
P/O
Now for the question:
The Stem Rule says NO window has (O + R).
Okay, so now we have (R + P)x2. This is because we must have either an O or a P in each window (Rule 4), and because we must have R x2.
So we can only have one window with O, and we must have at least two with P.
Let's update our Model:
P R ___ ___
P R ___ ___
O ___ ___ ___
Y can't go with O, so let's stick in one of the other windows (they're the same, so just pick one).
P R Y ___
P R ___ ___
O ___ ___ ___
But we still haven't taken care of Rule 1. When we do that, we get two scenarios:
Scenario 1:
P R Y ___
P R ___ ___
O G P ___
Scenario 2:
P R Y ___
P R G ___
O G? P? ___
Q 13:
(A) No.
(B) No.
(C) No.
(D) No.
(E) This is our top row. No need to spend a whole lotto time looking over the other choices.
Here's the setup:
G, O, P, R, Y
Rule 1: (G + P) x1 *exactly*
Rule 2: R x2 *exactly*
Rule 3: Y --> ~G, ~O
Rule 4: ~P --> O
CPos 3: (O or G) --> ~Y
CPos 4: ~O --> P
Rule 3 + CPos 4: Y --> ~O --> P
___ ___ ___ ___
P/O
___ ___ ___ ___
P/O
___ ___ ___ ___
P/O
Now for the question:
The Stem Rule says NO window has (O + R).
Okay, so now we have (R + P)x2. This is because we must have either an O or a P in each window (Rule 4), and because we must have R x2.
So we can only have one window with O, and we must have at least two with P.
Let's update our Model:
P R ___ ___
P R ___ ___
O ___ ___ ___
Y can't go with O, so let's stick in one of the other windows (they're the same, so just pick one).
P R Y ___
P R ___ ___
O ___ ___ ___
But we still haven't taken care of Rule 1. When we do that, we get two scenarios:
Scenario 1:
P R Y ___
P R ___ ___
O G P ___
Scenario 2:
P R Y ___
P R G ___
O G? P? ___
Q 13:
(A) No.
(B) No.
(C) No.
(D) No.
(E) This is our top row. No need to spend a whole lotto time looking over the other choices.