Replies to This Thread: 0
|
----
Posted: 05/25/2012 17:22
Always, for problems like this, draw the spaces:
___ ___ ___ ___ ___ ___
1 2 3 4 5 6
Then write out the rules:
1) & 3) T < Y < R
2) S < X
4) R must be 1, 2, 3, 4
Now analyze.
Since R > Y > T, we must leave 2 spaces for T and Y. That means R can only be in 3 or 4. We have 1 employee being limited to 1 of only 2 possible spaces.
Analyze further. Since R is limited to 3 and 4, Y is also limited to 2 or 3, and T is limited to 1 or 2. So we have 2 additional employees being limited to 1 of only 2 possible spaces.
Analyze further.
Put R in 3.
_T_ _Y_ _R_ ___ ___ ___
1 2 3 4 5 6
By rule 2, S can only be in 4 or 5, and X can only be in 5 or 6, because we need to leave a space for V. V can be in 4, 5, or 6.
Put R in 4.
___ ___ ___ _R_ ___ ___
1 2 3 4 5 6
By rule 2, S can be in 1, 2, or 3 (swappable with T, Y), which forces X to be in 5 or 6. V will be in 5 or 6, whichever is unoccupied by X.
If S is in 5, X can only be in 6. V is forced to be in 1, 2, or 3 (whichever is unoccupied by T, Y).
So, we have X as the other employee with only 1 of 2 possible spaces, i.e., 5 and 6. S can be in 1, 2, 3, 4, or 5, whereas V can be in 1, 2, 3, 4, 5, or 6.
Total, we have 4 employees: R, Y, T, and X that are limited to 1 out of 2 possible spaces.