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Image
(A)    1/5
(B) ...
(C) ...
(D) ...
(E) ...

*This question is included in Nova Math - Problem Set O: Fractions & Decimals

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Posted: 07/25/2012 20:57
It's been a very longtime since I have seen this kind of problem and the examinations does help. Can you please explain hat happened up top?
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Posted: 07/25/2012 21:00
Wow I'm tired. The explanation is not helping. How did it go from 6^4-6^3. To 6^3(6-1)
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Posted: 07/25/2012 23:05
Cef, that's just distributive property. 6*6^3 -1*6^3 = 6^4 - 6^3.
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Posted: 10/18/2013 11:55
I still can't see how that makes sense. I need to brush up on dist. property.
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Posted: 11/14/2013 16:12
Yes this makes no sense please explain in more detail
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Posted: 11/14/2013 16:57
Pamela, 6^4 (btw, ^ means "raised to the power of") is equal to 6*6*6*6 or 6^3 * 6, right? So 6^4 - 6^3 = 6^3 (6 - 1). That's just the distributive property of multiplication. ax - bx = x (a-b). In this case, x is 6^3, a=6, and b =1.

So we get 6^3 * 5 in the numerator, and 5 cancels the 5 in the denominator. And we are left with 6^3.
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