Define a @ b to be a3 – 1.
Column A
Column B
... ...
Define
a @
b to be
a3 – 1.
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Column A |
Column B |
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x @ 1 |
x @ 10 |
(A) Column A is larger
(B) ...
(C) ...
(D) ...
(E) ...
*This question is included in
Nova Math - Diagnostic/Review:
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Posted: 04/14/2012 15:29
How they come to this conclusion? Why x^3-1 is equal at x@10?
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Posted: 04/15/2012 07:44
have no idea why come to this conclusion
Contributor
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Posted: 04/16/2012 00:16
Hi Tanya and Vicki. This is a defined function question. It is always useful to think of, or restate the defined function formally as ƒ(x). In this case, a@b can be written as ƒ(a,b) = a^3-1, hence b doesn't play a part at all. Hence in x@1, you can ignore 1. It is ƒ(x) = x^3 - 1. The same goes for x@10, you can ignore 10 since the b part or 10 does not play a role. So x@10=ƒ(x) = x^3 -1.
Hence they are equal.
Reply 1 of 2
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Posted: 04/16/2012 02:14
Aaaaah, ok... Now I understand !!!
Thanks a lot)))
Reply 2 of 2
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Posted: 04/16/2012 19:10
Done))
Contributor
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Posted: 04/16/2012 02:17
You are welcome Tanya. Please don't forget to rate us in the App Store. Thanks for using our app and good luck in your preparation.
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Posted: 04/17/2012 06:52
It's very nice of you to help me to work out problem in such short time. Thank you so much! I won't forget to comment on app store^^
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Posted: 08/21/2013 18:29
I need more explanation to this problem... I'm kinda confused
Admin
Reply 1 of 1
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Posted: 08/30/2013 12:43
Paul, Joel Brainer posted a good explanation. Please look up the thread. Thanks.
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Define a @ b to be a3 – 1.
Column A
Column B
... ...
Posted: 11/06/2013 12:22
Why does column B not = x3-10?
Including the "b" in the initial statement makes it seem that the second number IS relevant.
Contributor
Reply 1 of 1
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Posted: 11/08/2013 15:07
Liam, "b" seems relevant, but it is not. The function's outcome is a^3 -1, not a^3-b.
