Column A p and q are consecutive even integers, and p − 2 and q + ... ...
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Posted: 03/19/2013 20:04
If you plug in the numbers, the results if p and q are not always even consecutive integers.
Contributor
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Posted: 03/19/2013 20:08
Maggie, please give an example of your concern.
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Posted: 05/15/2013 10:05
How can p and q have different values in the same problem? It get's extremely ardous if one has to suspect that for 2 + x = 4y and 3y - 3 = x; x and y would have to be solved for independently/equation? Of course that's not the case; but why here?
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Posted: 05/15/2013 10:07
Haha sorry, read it w/o paying attention....!
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Column A p and q are consecutive even integers, and p − 2 and q + ... ...
Posted: 08/12/2013 06:01
The word consecutive is misleading here. Like 4 and 6 are consecutive even numbers but not 4 and 8. Are 6 and 4 considered consecutive numbers since they are in reversing order?
Admin
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Posted: 08/12/2013 14:28
Hi Phillip,
If a sequence of even integers is such that each number is 2 more (or 2 less) than the immediately preceeding number, then it is a sequence of CONSECUTIVE even integers.
Therefore, 4 and 8 are not consecutive even integers because 8 is not 2 units greater than 4.
Now, 4 and 6 are are consecutive even integers because 6 is 2 units greater than 4.
Changing the normal left-to-right order in which we mention consecutive even integers (that is, 6 and 4) does not effect whether they are consecutive even integers. The following two lists represent the same set of consecutive even integers:
2, 4, 6, 8, ...
..., 8, 6, 4, 2
Nova Press
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Column A p and q are consecutive even integers, and p − 2 and q + ... ...
Posted: 12/16/2013 15:51
The offered solution required an assumption that p precedes q. Just because p is before q in the alphabet, does not mean that q cannot precede p in the problem. I think the problem should indicate p and q are consecutive, and p precedes or is less than q.
Admin
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Posted: 12/16/2013 16:54
Mark, not at all. The offered solution checks for both possibilities (whether p precedes or is less than q, and whether p follows or is larger than q), and finds that p is larger than q.
