If x+ y = k, then 3x 2 + 6xy + 3y 2 =

If x + y = k, then 3x 2 + 6xy + 3y2 =
(A)         k
(B) ...
(C) ...
(D) ...
(E) ...

*This question is included in Nova Press: Problem Solving Diagnostic Test

 
Replies to This Thread: 0 | ----
 
Posted: 05/16/2012 21:59
When i get to the part of perfect square trinomial i get lost and dont understand how to continue the problem to get the answer 3k^2
Arcadia
Admin
 
Replies to This Thread: 1 | ----
 
Posted: 05/17/2012 00:48
Liz, it's simply reducing the polynomial into its perfect square form. See the attached for how (x+y)^2 is expanded into the polynomial. The solution step you were referring to is simply doing the reverse. You should memorize this algebraic identity.
Reply 1 of 1
Replies to This Thread: 0 | ----
 
Posted: 12/28/2012 21:44
Arcadia. You are a genius. So simple and yet so complex. Thanks
 
Replies to This Thread: 0 | ----
 
Posted: 05/17/2012 12:08
Okay i see now thank You for the help!
 
Replies to This Thread: 1 | ----
If x+ y = k, then 3x 2 + 6xy + 3y 2 = 
Posted: 07/28/2016 11:18
Can you walk me through this problem? I'm not quite grasping it
Arcadia
Admin
Reply 1 of 1
Replies to This Thread: 0 | ----
 
Posted: 07/28/2016 15:40
Hi Chelsea,

In the method shown above, we manipulated the expression 3x^2 + 6xy + 3y^2 to dig out the expression x + y and then replaced x + y with k. Let's do this again and show a few more steps:

3x^2 + 6xy + 3y^2 =
3(x^2 + 2xy + y^2 ) = by factoring out the common factor 3
3(x + y)^2 = by the perfect square trinomial formula x^2 + 2xy + y^2 = (x + y)^2

Notice that we have now dug out the expression x + y, and we are give that x + y equals k. So, replacing x + y in the expression 3(x + y)^2 with k yields

3(k)^2 =

3k^2 by dropping the unnecessary parentheses.

Nova Press