If you use the "Reduce" button twice, you'll see the following text:


Inferences:
1. Since the fifth digit of the code must be more than the third, the fifth digit cannot be zero.

2. The second digit must be twice the first, and the only numbers available for the code are 1, 2, 3, 4, 5. Therefore, you can infer that one of the following two scenarios will arise:

Scenario A:
1 2 __ __ __

In scenario A, the 3RD slot can have either 0 OR 3, and the 5TH slot can have either 3 OR 4.


Scenario B:

2 4 __ __ __

In scenario A, the 3RD slot can have either 0 OR 1, and the 5TH slot can have either 1 OR 3.

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This one requires a little experimentation. However, since it's the last question, you should be pretty familiar with the rules of the game by now. This will help.

Choice "A": We know that zero can be 4TH from a previous question. So let's try 0 4TH with scenario A:
1, 2, 3, 0, 4.
This shows that choice "A" is wrong.

Choice "B": Scenario A has no space between 1 and 2. Strike choice "B".

Choice "C": Is it possible for there to be three spaces between 1 and 3? Let's try it with 1 in 1ST (which is scenario A). We know that we want 3 to be 5TH, so how about:
1, 2, 0, 4, 3.
This works. We have MORE THAN two spaces between 1 and 3. Strike choice "C".

Choice "D": Let's start with scenario B here. We'll try to put 2 1ST and 3 5TH:
2, 4, 0, 4, 3
This works, so we can strike choice "D".

Choice "E": This better work, because if it doesn't we've done something wrong up to this point. Let's look at our two scenarios:

Scenario A:
1 2 __ __ __

For scenario A, if 4 were 5TH, you still wouldn't have MORE than two spaces between 2 and 4. So this checks out.

Scenario B:
2 4 __ __ __

For scenario B, 2 is right next to 4. This checks out.

Choice "E" is correct.

Reply:

Choice E says that it MUST BE TRUE that there are "AT MOST" two digits between 2 and 4.

So you could have:
2, 4
or
2, __, 4
or
2, __, __ 4
and this answer choice would still be correct.

Yeah I read the question wrong!