Forgot Password?
 
Links
About Arcadia LSAT Shorthand NotationArcadia Prep's GMAT CourseArcadia Prep's LSAT CourseArcadia Prep's SAT CourseArcadia Prep's GRE CourseThe Simply Brilliant GMAT AppAbout the MCATMCAT Physical and Biological SciencesAbout Arcadia Prep's MCAT CourseTerms of SaleTerms of UseAbout Arcadia Apps
iPhone App Store
GGRE Prep App
GMAT Prep App
LSAT Prep App
LSAT Prep
SAT Prep App
 
Back to Questions

When a helium nucleus is formed, there is always some degree of loss of ... ...

When a helium nucleus is formed, there is always some degree of loss of mass. If the loss of mass equals 3.1 x 10–5 kg during the formation of one mol of it, what is the binding energy?  
(A) 3.1 x 10–5 J
(B) ...
(C) ...
(D) ...
(E) ...

*This question is included in 13. Radioactivity

Collapse All Subordinate Threads
Image Not Available
Contributor
 
Replies to This Thread: 1 | ----
When a helium nucleus is formed, there is always some degree of loss of ... ... 
Posted: 07/26/2013 18:42
Shouldn't it be c
Image Not Available
Reply 1 of 1
Replies to This Thread: 1 | Hide
 
Posted: 12/14/2015 16:44
Reply: agreed, according to the formula it should be c
Arcadia
Admin
Reply 1 of 1
Replies to This Thread: 0 | ----
 
Posted: 12/15/2015 02:59
Hi James,

Note that the 10^8 is squared, so it becomes 10^16. Multiplying this by 10^-5 yields

10^-5 x 10^16 = 10^11

Now, writing 28 in scientific notation yields 2.8 x 10^1. Multiplying this by 10^11 yields

(2.8 x 10^1)(10^11) = 2.8 x 10^12

Nova Press
Arcadia Prep © 2012.
Contact Arcadia  |  Terms of Use  |  Terms of Sale  |  Change Log-in Info