4/(1/3+1)

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(A) 1
(B) ...
(C) ...
(D) ...
(E) ...

*This question is included in Nova Math - Diagnostic: Test / Review

 
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Posted: 03/10/2012 19:20
Hi,
Can someone explain the process for doing this problem.

Thanks!
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Posted: 12/28/2012 13:07
4/1/3+1
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Posted: 03/10/2012 20:36
Emily, thanks for using the app.

First, do the denominator: ⅓ + 1 = ⅓ + 3 ⁄3 = 4⁄3.
Second, flip the denominator "upstairs" to the numerator (when you divide by a fraction, it's the same as multiplying by its inverse): 4 * ¾ = ...
 
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Posted: 05/31/2012 23:05
Wy is 1/3 = 3/3?
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Posted: 06/01/2012 17:42
4 / ( 1/3 + 1 )
Our fraction has yet another fraction in the denominator, to solve or simplify the fraction in the denominator we have to add 1/3 + 1
Being able to add two fractions requires the denominator to be equal, the 1 can be converted to the fraction 3/3 now we'll do our addition:
1/3 + 3/3 = 4/3
Now we have 4 / (4/3) and yet still a fraction in the denominator and when we have either a fraction in the numerator or denominator we convert also the other one into a fraction, thus 4 becomes 4/1 and we get:
(4/1) / (4/3) in order to divide two fractions we exchange both numerator and denominator of the second fraction to convert the sum from division into a multiplication thus (4/3) becomes (3/4) so we'll get:
(4/1) * (3/4) = (4*3) / (1*4) = 12 / 4 = 3
If you're familiar with fractions you can (cross) simplify (4/1) * (3/4) into (1/1) * (3/1) = 1 * 3 = 3
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Posted: 06/01/2012 02:03
Geraldo, I think you misunderstood the steps.
 
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4/(1/3+1) 
Posted: 05/11/2013 15:09
What is the answer to this question?
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Posted: 05/14/2013 14:48
Maggie Matt, what device are you using? The answer key can be accessed after you have made a choice. You can look up the answer, or continue to the next question.