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Posted: 11/30/2011 15:11
Hi Ielisa,
Let's start with what we know.
We know that W is in C1, and C1 is the only Center with W. (Stem Rule)
We also know that W → N. So C1 must have W + N.
Now, recall that C2 must have at least two items, and that C1 can have at most three items.
Since ALL items recycled in C2 must also be recycled in C1, we can infer that N must be recycled in C2.
(This must be true because the other item in C1, Wood, can ONLY be recycled in C1, and there can be AT MOST one item in C1 that is not also in C2.)
So now we know the following:
C1: N, W
C2: N
C3:
Another thing we know is that the 2nd item at C2 cannot be P (because P can only be recycled x1). And we also know that P cannot be at C1, because C1 already has one item NOT in C2 (that item is W).
So then, P must be in C3.
Now we have:
C1: N, W
C2: N
C3: P
And since G must be in a different center than P (Rule 3), we've got to put it in C1 AND C2. (Remember, we were looking for the second item that is shared between C2 and C1.)
Now we have:
C1: N, W, G
C2: N, G
C3: P
Finally, we've got to put T somewhere. Oh look, C3 needs another item.
Now we have:
C1: N, W, G
C2: N, G
C3: P, T
Now, you MAY be thinking "what if C3 has a third item?"
Ignore that thought for now. Let's look at the answer choices.
(A) This is C3, so this is our answer.
(B) Nope. C1 is the center with W, and it has N, W, G
(C) Nope. C3 has T, but no N.
(D) No. Again, C1 is the only center with W, and it has N, W, G.
(E) No again. C3 has T & P, not T, & G.
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Thanks,
Brendan Duffy
Founder, Arcadia Prep